pH Calculator
Convert between pH, pOH, [H⁺] and [OH⁻] for aqueous solutions at 25 °C.
Step-by-step working
- Convert input to [H⁺] (using Kw = 1.0 × 10⁻¹⁴ at 25 °C if needed)
- pH = −log₁₀[H⁺]; pOH = 14 − pH
Mathematical Formula
Overview & Explanation
pH expresses hydrogen-ion activity on a log scale; for dilute solutions concentration approximates activity.
How It Works
- Convert the input to [H⁺].
- Take −log₁₀.
- Derive pOH and [OH⁻] using Kw.
Practical Applications
- Chemistry labs.
- Pool and aquarium water.
The pH formula
pH = -log10[H+], where [H+] is the hydrogen ion concentration in mol/L. A concentration of 0.001 M gives pH 3. A concentration of 2.5 x 10^-4 M gives -log10(0.00025) = 3.60.
Because the scale is logarithmic, each whole unit is a tenfold change. A solution at pH 3 has ten times the hydrogen ion concentration of one at pH 4 and a hundred times that of pH 5.
pOH and bases
At 25 degrees C, pH + pOH = 14, where pOH = -log10[OH-]. A 0.01 M sodium hydroxide solution has [OH-] = 0.01, so pOH = 2 and pH = 12. The sum of 14 holds at 25 degrees C and shifts slightly at other temperatures.
Example 1: [H⁺] = 0.001 M
pH 3.
Inputs
I know: [H⁺] (mol/L) · Value: 0.001
Step 1
Convert input to [H⁺] (using Kw = 1.0 × 10⁻¹⁴ at 25 °C if needed)
Step 2
pH = −log₁₀[H⁺]; pOH = 14 − pH
pH
Result
Example 2: [OH⁻] = 0.01 M
pH 12.
Inputs
I know: [OH⁻] (mol/L) · Value: 0.01
Step 1
Convert input to [H⁺] (using Kw = 1.0 × 10⁻¹⁴ at 25 °C if needed)
Step 2
pH = −log₁₀[H⁺]; pOH = 14 − pH
pH
Result
How it's calculated & sources
pH = −log₁₀[H⁺]; pOH = 14 − pH; [H⁺][OH⁻] = Kw = 1.0 × 10⁻¹⁴ at 25 °C.
Frequently Asked Questions
Is pH + pOH always 14?
Can pH be negative?
Strong vs weak acids?
Can pH be below 0 or above 14?
Is this accurate for weak acids?
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